Prison Break Codeforces Round #709 Div. 2 Solution

Prison Break solution codeforces

Michael is accused of violating the social distancing rules and creating a risk of spreading coronavirus. He is now sent to prison. Luckily, Michael knows exactly what the prison looks like from the inside, especially since it’s very simple.

The prison can be represented as a rectangle a×ba×b which is divided into abab cells, each representing a prison cell, common sides being the walls between cells, and sides on the perimeter being the walls leading to freedom. Before sentencing, Michael can ask his friends among the prison employees to make (very well hidden) holes in some of the walls (including walls between cells and the outermost walls). Michael wants to be able to get out of the prison after this, no matter which cell he is placed in. However, he also wants to break as few walls as possible.

Your task is to find out the smallest number of walls to be broken so that there is a path to the outside from every cell after this.Input Prison Break solution codeforces

The first line contains a single integer tt (1≤t≤1001≤t≤100) — the number of test cases.

Each of the following tt lines contains two integers aa and bb (1≤a,b≤1001≤a,b≤100), representing a corresponding test case.Output Prison Break solution codeforces

For each test case print the single integer on a separate line — the answer to the problem.ExampleinputCopy

2
2 2
1 3

output Prison Break solution codeforcesCopy

4
3

Note

Some possible escape plans for the example test cases are shown below. Broken walls are shown in gray, not broken walls are shown in black.

Prison Break Codeforces Round #709 Div. 2 Solution
Prison Break Codeforces Round #709 Div. 2 Solution

Answer:

include

using namespace std;

int main() {
int t;
cin >> t;
while(t–)
{
int a,b;
cin>>a>>b;
cout<<a*b<<endl;
}
return 0;
}

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